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3-2.Motion in Plane
medium
If speed of a particle moving in a circle of radius $2\,m$ is given as $v = 2t + 2$, then its centripetal acceleration after $1\, s$ will be ......... $m/s^2$
A$8$
B$4$
C$2$
D$\sqrt {68}$
Solution
$v=2 t+2$
$\mathrm{v}_{\mathrm{t}=1}=4 \mathrm{m} / \mathrm{s}$
$a_{c p}=\frac{v^{2}}{r}=\frac{16}{2}=8$
$\mathrm{v}_{\mathrm{t}=1}=4 \mathrm{m} / \mathrm{s}$
$a_{c p}=\frac{v^{2}}{r}=\frac{16}{2}=8$
Standard 11
Physics
