If gravitational potential on surface of earth is V_0 , then potential at a point at height half of

English

Gujarati

Hindi

7.Gravitation

normal

If the gravitational potential on the surface of earth is $V_0$, then potential at a point at height half of the radius of earth is ..........

A

$\frac{V_0}{2}$

B

$\frac{2}{3} V_0$

C

$\frac{V_0}{3}$

D

$\frac{3 V_0}{2}$

Solution

(b)

Gravitational potential on the surface,

$V_0=-\frac{G M_e}{R_e}$

Gravitational potential at height $h$,

$V_n=-\frac{G M_\theta}{\left(R_\theta+\frac{R_\theta}{2}\right)}$

$=-\frac{2}{3} \frac{G M_\theta}{R_\theta}$

$=\frac{2}{3} V_0$

Standard 11

Physics

Share

Similar Questions

If $v_e$ is escape velocity and $v_0$ is orbital velocity of satellite for orbit close to the earth's surface. Then these are related by

normal

A particle of mass $M$ is at a distance $'a'$ from surface of a thin spherical shell of uniform equal mass and having radius $a$

normal

Two spheres of masses $m$ and $M$ are situated in air and the gravitational force between them is $F$ . the space around the masses is now filled with a liquid of specific gravity $3$ . The gravitational force between bodies will now be

normal

The escape velocity from a planet is $V_e.$ A tunnel is dug along the diameter of the planet and a small body dropped into it. The speed of the body at the centre of the planet will be

normal

A spherical planet far out in space has a mass ${M_0}$ and diameter ${D_0}$. A particle of mass m falling freely near the surface of this planet will experience an acceleration due to gravity which is equal to

normal