- Home
- Standard 11
- Physics
1.Units, Dimensions and Measurement
hard
જો ભૌતિક રાશિનું પરિમાણ $M^aL^bT^c$ વડે આપવામાં આવે, તો ભૌતિક રાશિ .......
Aવેગ હોય જો $a=1,b=0,c=-1$
Bપ્રવેગ હોય જો $a=1,b=1,c=-2$
Cબળ હોય જો $a=0,b=-1,c=-2$
Dદબાણ હોય જો $a=1,b=-1,c=-2$
(AIPMT-2009)
Solution
$\begin{array}{l}
\Pr essure,\,p = \frac{{force}}{{area}} = \frac{{mass\, \times \,acceleration}}{{area}}\\
\therefore \,\left[ P \right] = \frac{{{M^1}L{T^{ – 2}}}}{{{L^2}}} = \left[ {{M^1}{L^{ – 1}}{T^{ – 2}}} \right] = \,{M^a}{L^b}{T^c}\\
\therefore \,a = 1,\,b = – 1,\,c = – 2.
\end{array}$
\Pr essure,\,p = \frac{{force}}{{area}} = \frac{{mass\, \times \,acceleration}}{{area}}\\
\therefore \,\left[ P \right] = \frac{{{M^1}L{T^{ – 2}}}}{{{L^2}}} = \left[ {{M^1}{L^{ – 1}}{T^{ – 2}}} \right] = \,{M^a}{L^b}{T^c}\\
\therefore \,a = 1,\,b = – 1,\,c = – 2.
\end{array}$
Standard 11
Physics
