If the electric field intensity in a fair wea | vedclass

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Question

(c)

$E=100 \frac{ V }{ m } \quad R=6400 \,km$

By Gauss law

$E A=\frac{q}{\varepsilon_0} \Rightarrow q=E A \varepsilon_0$

$\Rightarrow q=20

Vedclass · Accepted Answer

$4.55 	imes 10^5$

Vedclass · Answer

(c)

$E=100 \frac{ V }{ m } \quad R=6400 \,km$

By Gauss law

$E A=\frac{q}{\varepsilon_0} \Rightarrow q=E A \varepsilon_0$

$\Rightarrow q=200\left(4 \pi\left(6400 	imes 10^3ight)^2ight) 	imes 8.85 	imes 10^{-12}$

$\Rightarrow q=4.55 	imes 10^5 \,C$

If the electric field intensity in a fair weather atmosphere is $100 \,V / m$, then the total charge on the earth's surface is ............ $C$ (radius of the earth is $6400\,km$ )

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