If electric flux entering and leaving an enclosed surface respectively is {varphi ₁} and {varphi ?

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1. Electric Charges and Fields

easy

If the electric flux entering and leaving an enclosed surface respectively is ${\varphi _1}$ and ${\varphi _2}$ the electric charge inside the surface will be

A

$({\varphi _1} + {\varphi _2}){\varepsilon _0}$

B

$({\varphi _2} - {\varphi _1}){\varepsilon _0}$

C

$({\varphi _1} + {\varphi _2})/{\varepsilon _0}$

D

$({\varphi _2} - {\varphi _1})/{\varepsilon _0}$

(AIEEE-2003)

Solution

(b) ${\varphi _{net}} = \frac{1}{{{\varepsilon _0}}} \times {Q_{enc}}$ $==>$ ${Q_{enc}} = ({\varphi _2} – {\varphi _1}){\varepsilon _0}$

Standard 12

Physics

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