If the following system of linear equations
$2 x+y+z=5$
$x-y+z=3$
$x+y+a z=b$
has no solution, then :
If the following system of linear equations
$2 x+y+z=5$
$x-y+z=3$
$x+y+a z=b$
has no solution, then :
- [JEE MAIN 2021]
- A
$\mathrm{a}=-\frac{1}{3}, \mathrm{~b} \neq \frac{7}{3}$
- B
$a \neq \frac{1}{3}, b=\frac{7}{3}$
- C
$\mathrm{a} \neq-\frac{1}{3}, \mathrm{~b}=\frac{7}{3}$
- D
$\mathrm{a}=\frac{1}{3}, \mathrm{~b} \neq \frac{7}{3}$
Similar Questions
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If $f(\theta ) =\left| {\begin{array}{*{20}{c}}
1&{\cos {\mkern 1mu} \theta }&1\\
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- [JEE MAIN 2014]
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- [IIT 2002]