If A = left| {,begin{array}{*{20}{c}}1&1&1a&b&c{{a^3}}&{{b^3}}&{{c^3}}end{ar

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3 and 4 .Determinants and Matrices

easy

If $A = \left| {\,\begin{array}{{20}{c}}1&1&1\\a&b&c\\{{a^3}}&{{b^3}}&{{c^3}}\end{array}\,} \right|,B = \left| {\,\begin{array}{{20}{c}}1&1&1\\{{a^2}}&{{b^2}}&{{c^2}}\\{{a^3}}&{{b^3}}&{{c^3}}\end{array}\,} \right|,C = \left| {\,\begin{array}{*{20}{c}}a&b&c\\{{a^2}}&{{b^2}}&{{c^2}}\\{{a^3}}&{{b^3}}&{{c^3}}\end{array}\,} \right|,$ then which relation is correct

A

$A = B$

B

$A = C$

C

$B = C$

D

None of these

Solution

(d) It is obvious.

Standard 12

Mathematics

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