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1.Relation and Function
hard
જો વિધેય $f\,:\,R - \,\{ 1, - 1\} \to A$ ; $f\,(x)\, = \frac{{{x^2}}}{{1 - {x^2}}}$ એ વ્યાપ્ત વિધેય હોય તો $A$ મેળવો .
A
$R\, - \,[ - 1,0)$
B
$R\, - \,( - 1,0)$
C
$R\, - \,\{ - 1\} $
D
$[0,\infty )$
(JEE MAIN-2019)
Solution
$y\, = \frac{{{x^2}}}{{1 – {x^2}}}$ Range of $y : R – [ – 1,0)$ for surjective function, $A$ must be same as above range.
Standard 12
Mathematics