If length of rod A is 3.25 pm 0.01 ,cm and that of B is 4.19 pm 0.01, cm then rod B is longer than r

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1.Units, Dimensions and Measurement

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If the length of rod $A$ is $3.25 \pm 0.01 \,cm$ and that of $B$ is $4.19 \pm 0.01\, cm $ then the rod $B$ is longer than rod $A$ by

A

$0.94 \pm 0.00 \,cm$

B

$0.94 \pm 0.01 \,cm$

C

$0.94 \pm 0.02 \,cm$

D

$0.94 \pm 0.005\, cm$

Solution

$x=(4.19 \pm 0.01)-(3.25 \pm 0.01)$

$x=(4.19-3.25) \pm(0.01+0.01)$

$x=0.94 \pm0.02$

Standard 11

Physics

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