If length of pendulum in pendulum clock increases by 0.1, % , then error in time per day is: (in s )

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10-1.Thermometry, Thermal Expansion and Calorimetry

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If the length of the pendulum in pendulum clock increases by $0.1\, \%$, then the error in time per day is: (in $s$)

A

$86.4$

B

$4.32$

C

$43.2$

D

$8.64$

(JEE MAIN-2021)

Solution

${T}=2 \pi \sqrt{\frac{\ell}{g}}$

$\frac{\Delta {T}}{{T}}=\frac{1}{2} \frac{\Delta \ell}{\ell}$

$\Delta {T}=\frac{1}{2} \times \frac{0.1}{100} \times 24 \times 3600$

$\Delta {T}=43.2$

Standard 11

Physics

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