If the momentum of a photon is $p$, then its frequency is
Where $m$ is the rest mass of the photon
If the momentum of a photon is $p$, then its frequency is
Where $m$ is the rest mass of the photon
- A
$\frac{{ph}}{c}$
- B
$\frac{{pc}}{h}$
- C
$\frac{{mh}}{c}$
- D
$\frac{{mc}}{h}$
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There are two sources of light, each emitting with a power of $100 \,W.$ One emits $X-$ rays of wavelength $1\, nm$ and the other visible light at $500\, nm$. Find the ratio of number of photons of $X-$ rays to the photons of visible light of the given wavelength ?
There are two sources of light, each emitting with a power of $100 \,W.$ One emits $X-$ rays of wavelength $1\, nm$ and the other visible light at $500\, nm$. Find the ratio of number of photons of $X-$ rays to the photons of visible light of the given wavelength ?
A radiation of energy $'E'$ falls normally on a perfectly reflecting surface. The momentum transferred to the surface is $( C =$ Velocity of light $)$
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- [AIPMT 2015]
By suitable example show that particle or wave nature depend on type of experiment.
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The minimum intensity of light to be detected by human eye is ${10^{ - 10}}W/{m^2}$. The number of photons of wavelength $5.6 \times {10^{ - 7}}m$ entering the eye, with pupil area ${10^{ - 6}}{m^2}$, per second for vision will be nearly
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