If the plates of a parallel plate capacitor connected to a battery are moved close to each other, then

$A$. the charge stored in it, increases.

$B$. the energy stored in it, decreases.

$C$. its capacitance increases.

$D$. the ratio of charge to its potential remains the same.

$E$. the product of charge and voltage increases.

Choose the most appropriate answer from the options given below:

The energy stored in a condenser of capacity $C$ which has been raised to a potential $V$ is given by

A capacitor of capacity $C_1$ is charged to the potential of $V_0$. After disconnecting with the battery, it is connected with a neutral capacitor of capacity $C_2$ as shown in the adjoining figure. The ratio of energy of system before and after the connection of switch $S$ will be

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A capacitor of capacity $C$ is connected with a battery of potential $V$ in parallel. The distance between its plates is reduced to half at once, assuming that the charge remains the same. Then to charge the capacitance upto the potential $V$ again, the energy given by the battery will be

A battery is used to charge a parallel plate capacitor till the potential difference between the plates becomes equal to the electromotive force of the battery. The ratio of the energy stored in the capacitor and the work done by the battery will be