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2. Electric Potential and Capacitance
easy
If the potential of the inner shell is $10\,V$ and that of the outer shell is $5\,V$, then potential at the centre will be....$V$

A
$10$
B
$5$
C
$15$
D
$0$
Solution
${{\rm{V}}_{{\rm{in}}}} = \frac{{{\rm{k}}{{\rm{Q}}_1}}}{{\rm{a}}} + \frac{{{\rm{k}}{{\rm{Q}}_2}}}{{2{\rm{a}}}} = 10\,{\rm{V}}$ (this will be constant for region from center to inner sphere surface)
$\mathrm{V}_{\mathrm{out}}=\frac{\mathrm{k} \mathrm{Q}_{1}}{2 \mathrm{a}}+\frac{\mathrm{kQ}_{2}}{2 \mathrm{a}}=5 \mathrm{\,V}$
Standard 12
Physics