If the present units of length. time and mass | vedclass

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Question

velocity $= m/sec ;$  in new system  $= \frac{{100m}}{{100\sec }} = \frac{m}{{\sec }}$ (same)
force $ = \frac{{kg 	imes m}}{{{{\sec }^2}}}

Vedclass · Accepted Answer

The new unit of force is decreased $\frac{1}{1000}$ times

Vedclass · Answer

velocity $= m/sec ;$  in new system  $= \frac{{100m}}{{100\sec }} = \frac{m}{{\sec }}$ (same)
force $ = \frac{{kg 	imes m}}{{{{\sec }^2}}}$; in new system $ = \frac{1}{{10}}kg 	imes \frac{{100m}}{{100\sec \, 	imes \,100\sec }}$ $ = \frac{1}{{1000}}\,\frac{{kg 	imes m}}{{{{\sec }^2}}}$
energy $ = \frac{{kg 	imes {m^2}}}{{{{\sec }^2}}}$ ; in new system $ = \frac{1}{{10}}kg 	imes \frac{{100m 	imes 100m}}{{100\sec \, 	imes \,100\sec }}$ $ = \frac{1}{{10}}\frac{{kg 	imes {m^{m{2}}}}}{{se{c^2}}}$
pressure $ = \frac{{kg}}{{m 	imes {{\sec }^2}}}$; in new system $ = \frac{1}{{10}}kg 	imes \frac{1}{{100}}m 	imes \frac{1}{{100\,sec 	imes 100\,sec}}$ $ = {10^{ - 7}}\frac{{kg}}{{m 	imes se{c^2}}}$

If the present units of length. time and mass $(m, s, k g)$ are changed to $100\; m, 100\; s$. $\frac{1}{10} \;k g$ then

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