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7.Binomial Theorem
medium
જો ${(x - 2y + 3z)^n}$ ના સહગુણકોનો સરવાળો $128$ હોય તો ${(1 + x)^n}$ ના વિસ્તરણમાં મહતમ સહગુણક મેળવો.
A
$35$
B
$20$
C
$10$
D
એકપણ નહિ.
Solution
(a) Sum of the coefficient in the expansion ${(x – 2y + 3z)^n}$ is ${(1 – 2 + 3)^2}$=$ {2^n}$
${2^n}$=$ 128$
$\Rightarrow n = 7$
Therefore, greatest coefficient in the expansion of ${(1 + x)^7}$is $^7{C_3}$or $^7{C_4}$ because both are equal to $35.$
Standard 11
Mathematics