If the three lines x - 3y = p, ax + 2y = q an | vedclass

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Question

Since three lines $x-3y=p$,

$ax+2y=q$ and $ax+y=r$

from aright angled triangle

$	herefore $ product of sloper of any two lines $=-1$

Supp

Vedclass · Accepted Answer

$a^2 -9a + 18 =0$

Vedclass · Answer

Since three lines $x-3y=p$,

$ax+2y=q$ and $ax+y=r$

from aright angled triangle

$	herefore $ product of sloper of any two lines $=-1$

Suppose $ax+2y=q$ and $x-3y=p$ are $ \bot $ to each other.

$	herefore \frac{{ - a}}{2} 	imes \frac{1}{3} =  - 1 \Rightarrow a = 6$

Now, consider option one by one $a=6$ satisfies noly option $(a)$

$	herefore $ Required answer is ${a^2} - 9a + 18 = 0$

If the three lines $x - 3y = p, ax + 2y = q$ and $ax + y = r$ form a right-angled triangle then

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