If the truth value of the statement $p \to \left( { \sim q \vee r} \right)$ is false $(F)$, then the truth values of the statement $p, q, r$ are respectively
$T, T, F$
$F, T, T$
$T, F, T$
$T, F, F$
$\sim p \wedge q$ is logically equivalent to
The statement $[(p \wedge q) \rightarrow p] \rightarrow (q \wedge \sim q)$ is
$\sim (p \wedge q)$ is equal to .....
$(p \to q) \leftrightarrow (q\ \vee \sim p)$ is
The statement $(\sim( p \Leftrightarrow \sim q )) \wedge q$ is :