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Mathematical Reasoning
medium
The conditional $(p \wedge q) ==> p$ is
A
A tautology
B
A fallacy $i.e.$, contradiction
C
Neither tautology nor fallacy
D
None of these
Solution
(a) $(p \wedge q) \Rightarrow p$ is a tautology.
|
$p$ |
$q$ |
|
$(p\wedge q)⇒p$ |
|
$T$ |
$T$ |
$T$ |
$T$ |
|
$T$ |
$F$ |
$F$ |
$T$ |
|
$F$ |
$T$ |
$F$ |
$T$ |
|
$F$ |
$F$ |
$F$ |
$T$ |
$p\wedge q$
Standard 11
Mathematics
