The conditional $(p \wedge q) ==> p$ is

Let $p , q , r$ be three statements such that the truth value of $( p \wedge q ) \rightarrow(\sim q \vee r )$ is $F$. Then the truth values of $p , q , r$ are respectively

The Boolean expression $\sim\left( {p\; \vee q} \right) \vee \left( {\sim p \wedge q} \right)$ is equivalent ot :

Among the two statements

$(S1):$ $( p \Rightarrow q ) \wedge( q \wedge(\sim q ))$ is a contradiction and

$( S 2):( p \wedge q ) \vee((\sim p ) \wedge q ) \vee$

$( p \wedge(\sim q )) \vee((\sim p ) \wedge(\sim q ))$ is a tautology

Statement $p$ $\rightarrow$  ~$q$ is false, if

$(p\; \wedge \sim q) \wedge (\sim p \wedge q)$ is