If two balanced dice are tossed once, probability of event, that sum of integers coming on upper sid

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14.Probability

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If two balanced dice are tossed once, the probability of the event, that the sum of the integers coming on the upper sides of the two dice is $9$, is

A

$\frac{7}{{18}}$

B

$\frac{5}{{36}}$

C

$\frac{1}{9}$

D

$\frac{1}{6}$

Solution

(c) Required probability $ = \frac{4}{{36}} = \frac{1}{9}.$

Standard 11

Mathematics

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