If two sets $A$ and $B$ have $99$ elements in common, then the number of elements common to the sets $A \times B$ and $B \times A$ is equal to
$2^{99}$
$(99)^2$
$100$
$18$
It is obvious
Let $A=\{1,2\}, B=\{1,2,3,4\}, C=\{5,6\}$ and $D=\{5,6,7,8\} .$ Verify that
$A \times(B \cap C)=(A \times B) \cap(A \times C)$
Let $A=\{1,2,3\}, B=\{3,4\}$ and $C=\{4,5,6\} .$ Find
$(A \times B) \cup(A \times C)$
If $A \times B =\{(p, q),(p, r),(m, q),(m, r)\},$ find $A$ and $B$
If $n(A) = 4$, $n(B) = 3$, $n(A \times B \times C) = 24$, then $n(C) = $
State whether each of the following statements are true or false. If the statement is false, rewrite the given statement correctly.
If $P=\{m, n\}$ and $Q=\{n, m\},$ then $P \times Q=\{(m, n),(n, m)\}.$
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