Let $A=\{1,2\}, B=\{1,2,3,4\}, C=\{5,6\}$ and $D=\{5,6,7,8\} .$ Verify that
$A \times(B \cap C)=(A \times B) \cap(A \times C)$
To verify: $A \times(B \cap C)=(A \times B) \cap(A \times C)$
We have $B \cap C=\{1,2,3,4\} \cap\{5,6\}=\varnothing$
$\therefore \mathrm{L .H. S .}=A \times(B \cap C)=A \times \varnothing=\varnothing$
$A \times B=\{(1,1),(1,2),(1,3),(1,4),(2,1),(2,2),(2,3),(2,4)\}$
$A \times C=\{(1,5),(1,6),(2,5),(2,6)\}$
$\therefore R H S=(A \times B) \cap(A \times C)=\varnothing$
$\therefore L.H.S.=R.H.S.$
Hence, $A \times(B \cap C)=(A \times B) \cap(A \times C)$
Let $A=\{1,2,3\}, B=\{3,4\}$ and $C=\{4,5,6\} .$ Find
$(A \times B) \cap(A \times C)$
$A = \{1,2,3,4......100\}, B = \{51,52,53,...,180\}$, then number of elements in $(A \times B) \cap (B \times A)$ is
If the set $A$ has $3$ elements and the set $B=\{3,4,5\},$ then find the number of elements in $( A \times B ).$
State whether each of the following statements are true or false. If the statement is false, rewrite the given statement correctly.
If $A=\{1,2\}, B=\{3,4\},$ then $A \times\{B \cap \varnothing\}=\varnothing$
If $G =\{7,8\}$ and $H =\{5,4,2\},$ find $G \times H$ and $H \times G$.