Let $A=\{1,2\}, B=\{1,2,3,4\}, C=\{5,6\}$ and $D=\{5,6,7,8\} .$ Verify that
$A \times(B \cap C)=(A \times B) \cap(A \times C)$
Let $A=\{1,2\}, B=\{1,2,3,4\}, C=\{5,6\}$ and $D=\{5,6,7,8\} .$ Verify that
$A \times(B \cap C)=(A \times B) \cap(A \times C)$
To verify: $A \times(B \cap C)=(A \times B) \cap(A \times C)$
We have $B \cap C=\{1,2,3,4\} \cap\{5,6\}=\varnothing$
$\therefore \mathrm{L .H. S .}=A \times(B \cap C)=A \times \varnothing=\varnothing$
$A \times B=\{(1,1),(1,2),(1,3),(1,4),(2,1),(2,2),(2,3),(2,4)\}$
$A \times C=\{(1,5),(1,6),(2,5),(2,6)\}$
$\therefore R H S=(A \times B) \cap(A \times C)=\varnothing$
$\therefore L.H.S.=R.H.S.$
Hence, $A \times(B \cap C)=(A \times B) \cap(A \times C)$
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