Let $A=\{1,2,3\}, B=\{3,4\}$ and $C=\{4,5,6\} .$ Find
$(A \times B) \cup(A \times C)$
Using the sets $A \times B$ and $A \times C$ from part $(ii)$ above, we obtain
$(A \times B) \cap(A \times C)=\{(1,4),(2,4),(3,4)\}$
$(A \times B) \cup(A \times C)=\{(1,3),(1,4),(1,5),(1,6),(2,3),(2,4),(2,5),(2,6)$
$(3,3),(3,4),(3,5),(3,6)\}$
$A = \{1,2,3,4......100\}, B = \{51,52,53,...,180\}$, then number of elements in $(A \times B) \cap (B \times A)$ is
If $R$ is the set of all real numbers, what do the cartesian products $R \times R$ and $R \times R \times R$ represent?
If $n(A) = 4$, $n(B) = 3$, $n(A \times B \times C) = 24$, then $n(C) = $
If two sets $A$ and $B$ are having $99$ elements in common, then the number of elements common to each of the sets $A \times B$ and $B \times A$ are
If $A=\{-1,1\},$ find $A \times A \times A.$