If velocity of particle moving along $x-$ axis is given as $v = k\sqrt x $ . Then ($a$ is acceleration)
If velocity of particle moving along $x-$ axis is given as $v = k\sqrt x $ . Then ($a$ is acceleration)
- A
$x \propto \sqrt t $
- B
$x \propto t$
- C
$a \propto x$
- D
$a =$ constant
Similar Questions
The velocity versus time graph of a body moving in a straight line is as shown in the figure below
The velocity versus time graph of a body moving in a straight line is as shown in the figure below
A particle moves towards east with velocity $5\, m/s$. After $10$ seconds its direction changes towards north with same velocity. The average acceleration of the particle is
A particle moves towards east with velocity $5\, m/s$. After $10$ seconds its direction changes towards north with same velocity. The average acceleration of the particle is
- [IIT 1982]
Which of the following speed-time $(v-t)$ graphs is physically not possible?
Which of the following speed-time $(v-t)$ graphs is physically not possible?
Velocity of a particle is in negative direction with constant acceleration in positive direction. Then, match the following columns.
Colum $I$
Colum $II$
$(A)$ Velocity-time graph
$(p)$ Slope $\rightarrow$ negative
$(B)$ Acceleration-time graph
$(q)$ Slope $\rightarrow$ positive
$(C)$ Displacement-time graph
$(r)$ Slope $\rightarrow$ zero
$(s)$ $\mid$ Slope $\mid \rightarrow$ increasing
$(t)$ $\mid$ Slope $\mid$ $\rightarrow$ decreasing
$(u)$ |Slope| $\rightarrow$ constant
Velocity of a particle is in negative direction with constant acceleration in positive direction. Then, match the following columns.
| Colum $I$ | Colum $II$ |
| $(A)$ Velocity-time graph | $(p)$ Slope $\rightarrow$ negative |
| $(B)$ Acceleration-time graph | $(q)$ Slope $\rightarrow$ positive |
| $(C)$ Displacement-time graph | $(r)$ Slope $\rightarrow$ zero |
| $(s)$ $\mid$ Slope $\mid \rightarrow$ increasing | |
| $(t)$ $\mid$ Slope $\mid$ $\rightarrow$ decreasing | |
| $(u)$ |Slope| $\rightarrow$ constant |
A train accelerates from rest at a constant rate $\alpha$ for distance $x_1$ and time $t_1$. After that it retards to rest at constant rate $\beta$ for distance $x_2$ and time $t_2$. Which of the following relations is correct?
A train accelerates from rest at a constant rate $\alpha$ for distance $x_1$ and time $t_1$. After that it retards to rest at constant rate $\beta$ for distance $x_2$ and time $t_2$. Which of the following relations is correct?