Area under acceleration-time graph gives

English

Gujarati

Hindi

2.Motion in Straight Line

easy

The area under acceleration-time graph gives

A

Distance travelled

B

Change in acceleration

C

Force acting

D

Change in velocity

Solution

(d)Acceleration$-$Time graph represents the object's change in velocity. Acceleration $=\frac{\Delta v}{\Delta t}$

Area between acceleration-time graph gives$:$

$a \times \Delta t=\frac{\Delta v}{\Delta t} \times \Delta t=\Delta v$

Standard 11

Physics

Share

Similar Questions

If the velocity $v$ of a particle moving along a straight line decreases linearly with its displacement $s$ from $20\,ms ^{-1}$ to a value approaching zero at $s=30\,m$, then acceleration of the particle at $s=15\,m$ is $……..$

medium

The deceleration experienced by a moving motor boat, after its engine is cut-off is given by $\frac{{dv}}{{dt}} = – k{v^3}$ , where $k$ is constant. If $v_0$ is the magnitude of the velocity at cut-off, the magnitude of the velocity at a time $t$ after the cut-off is

hard

Will the acceleration increase or decrease with increase in velocity ?

medium

At time $t=0$, a car moving along a straight line has a velocity of $16 \;m / s$. It slows down with an acceleration of $-0.5 t \;m / s ^2$, where $t$ is in second. Mark the correct statement (s).

hard

A street car moves rectilinearly from station $A$ to the next station $B$ with an acceleration varying according to the law $a=(b-c x)$, where $b$ and $c$ are constants and $x$ is the distance from station $A$. The distance between the two stations and the maximum velocity are

hard