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3-2.Motion in Plane
medium
If we can throw a ball upto a maximum height $H$, the maximum horizontal distance to which we can throw it is
A
$2\,H$
B
$\sqrt 2 \,H$
C
$H$
D
$\frac{H}{2}$
(AIIMS-2011)
Solution
$\begin{array}{l}
H = \frac{{{u^2}}}{{2g}} \Rightarrow {u^2} = 2gH\\
For\,{\rm{maximum}}\,horizontal\,{\rm{distance}}\\
{X_{\max }} = \frac{{{u^2}}}{g} = \frac{{2gH}}{g} = 2H
\end{array}$
Standard 11
Physics
