14.Waves and Sound
medium

If you set up the seventh harmonic on a string fixed at both ends, how many nodes and antinodes are set up in it

A

$8, 7$

B

$7, 7$

C

$8, 9$

D

$9, 8$

Solution

(a) String will vibrate in $7$ loops so it will have $8$ nodes $7$ antinodes. 

Number of harmonics = Number of loops = Number of antinodes

$⇒$ Number of antinodes $= 7$

Hence number of nodes = Number of antinodes $+ 1 = 7 + 1 = 8$

Standard 11
Physics

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