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14.Waves and Sound
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If you set up the seventh harmonic on a string fixed at both ends, how many nodes and antinodes are set up in it
A
$8, 7$
B
$7, 7$
C
$8, 9$
D
$9, 8$
Solution
(a) String will vibrate in $7$ loops so it will have $8$ nodes $7$ antinodes.
Number of harmonics = Number of loops = Number of antinodes
$⇒$ Number of antinodes $= 7$
Hence number of nodes = Number of antinodes $+ 1 = 7 + 1 = 8$
Standard 11
Physics