In ${\left( {\sqrt[3]{2} + \frac{1}{{\sqrt[3]{3}}}} \right)^n}$ if the ratio of ${7^{th}}$ term from the beginning to the ${7^{th}}$ term from the end is $\frac{1}{6}$, then $n = $

  • A

    $7$

  • B

    $8$

  • C

    $9$

  • D

    None of these

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  • [JEE MAIN 2019]