In a balanced Wheatstone’s network, resistances in arms Q and S are interchanged. As a result

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3.Current Electricity

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In a balanced Wheatstone’s network, the resistances in the arms $Q$ and $S$ are interchanged. As a result of this

A

Network is not balanced

B

Network is still balanced

C

Galvanometer shows zero deflection

D

Galvanometer and the cell must be interchanged to balance

Solution

We know that in In a balanced Wheatstone's network,

$\frac{ P }{ Q }=\frac{ R }{ S }$

If $Q$ is replaced by $S$ then ratio becomes $\frac{P}{S}=\frac{R}{Q}$ which is not equal to the previous ratio. Hence, network is not balanced.

Standard 12

Physics

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