In a circus, a performer throws an apple towards a hoop held at $45 \,m$ height by another performer standing on a high platform (see figure). The thrower aims for the hoop and throws the apple with a speed of $24 \,m / s$. At the exact moment that the thrower releases the apple, the other performer drops the hoop. The hoop falls straight down. At ............ $m$ height above the ground does the apple go through the hoop?
In a circus, a performer throws an apple towards a hoop held at $45 \,m$ height by another performer standing on a high platform (see figure). The thrower aims for the hoop and throws the apple with a speed of $24 \,m / s$. At the exact moment that the thrower releases the apple, the other performer drops the hoop. The hoop falls straight down. At ............ $m$ height above the ground does the apple go through the hoop?
- [KVPY 2020]
- A
$21$
- B
$22$
- C
$23$
- D
$24$
Similar Questions
A projectile is fired at $30^{\circ}$ to the horizontal, The vertical component of its velocity is $80 \;ms ^{-1}$, Its time flight is $T$. What will be the velocity of projectile at $t =\frac{ T }{2}$?
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A particle is projected from the ground at an angle of $\theta $ with the horizontal with an initial speed of $u$. Time after which velocity vector of the projectile is perpendicular to the initial velocity is
A particle is projected from the ground at an angle of $\theta $ with the horizontal with an initial speed of $u$. Time after which velocity vector of the projectile is perpendicular to the initial velocity is
Column $-I$
Angle of projection
Column $-II$
$A.$ $\theta \, = \,{45^o}$
$1.$ $\frac{{{K_h}}}{{{K_i}}} = \frac{1}{4}$
$B.$ $\theta \, = \,{60^o}$
$2.$ $\frac{{g{T^2}}}{R} = 8$
$C.$ $\theta \, = \,{30^o}$
$3.$ $\frac{R}{H} = 4\sqrt 3 $
$D.$ $\theta \, = \,{\tan ^{ - 1}}\,4$
$4.$ $\frac{R}{H} = 4$
$K_i :$ initial kinetic energy
$K_h :$ kinetic energy at the highest point
|
Column $-I$ Angle of projection |
Column $-II$ |
| $A.$ $\theta \, = \,{45^o}$ | $1.$ $\frac{{{K_h}}}{{{K_i}}} = \frac{1}{4}$ |
| $B.$ $\theta \, = \,{60^o}$ | $2.$ $\frac{{g{T^2}}}{R} = 8$ |
| $C.$ $\theta \, = \,{30^o}$ | $3.$ $\frac{R}{H} = 4\sqrt 3 $ |
| $D.$ $\theta \, = \,{\tan ^{ - 1}}\,4$ | $4.$ $\frac{R}{H} = 4$ |
$K_i :$ initial kinetic energy
$K_h :$ kinetic energy at the highest point
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