Maximum height reached by a projectile is 64 mathrm{~m} . If initial velocity is halved, new maximum

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3-2.Motion in Plane

hard

The maximum height reached by a projectile is $64 \mathrm{~m}$. If the initial velocity is halved, the new maximum height of the projectile is_________.$\mathrm{m}$.

A

$11$

B

$14$

C

$15$

D

$16$

(JEE MAIN-2024)

Solution

$\mathrm{H}_{\max }=\frac{\mathrm{u}^2 \sin ^2 \theta}{2 \mathrm{~g}}$

$\frac{\mathrm{H}_{1 \max }}{\mathrm{H}_{2 \max }}=\frac{\mathrm{u}_1^2}{\mathrm{u}_2^2}$

$\frac{64}{\mathrm{H}_{2 \max }}=\frac{\mathrm{u}^2}{(\mathrm{u} / 2)^2}$

$\mathrm{H}_{2 \max }=16 \mathrm{~m}$

Standard 11

Physics

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