In a hollow spherical shell, potential (V) changes with respect to distance (s) from centre as

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1. Electric Charges and Fields

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In a hollow spherical shell, potential $(V)$ changes with respect to distance $(s)$ from centre as

A

B

C

D

Solution

In shell, $q$ charge is uniformly distributed over its surface, it behaves as a conductor.

$\mathrm{V}=$ potential at surface $=\frac{\mathrm{q}}{4 \pi \varepsilon_{0} \mathrm{R}}$ and

inside $\mathrm{V}=\frac{\mathrm{q}}{4 \pi \varepsilon_{0} \mathrm{R}}$

Because of this it behaves as an equipotential surface.

Standard 12

Physics

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