Gujarati
13.Nuclei
easy

In a radioactive reaction $_{92}{X^{232}}{ \to _{82}}{Y^{204}}$, the number of $\alpha - $ particles emitted is

A

$7$

B

$6$

C

$5$

D

$4$

Solution

(a) By using ${n_\alpha } = \frac{{A – A'}}{4}$$ = \frac{{232 – 204}}{4} = 7$.

Standard 12
Physics

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