10-2.Transmission of Heat
normal

In a room where the temperature is ${30^o}C$, a body cools from ${61^o}C$ to ${59^o}C$ in $4$ minutes. The time (in min.) taken by the body to cool from ${51^0}C$ to ${49^0}C$ will be ....... $\min$

A$4$
B$6$
C$5$
D$8$

Solution

(b) First case, $\frac{{61 – 59}}{4} = K\left[ {\frac{{61 + 59}}{2} – 30} \right]$…..$(i)$
Second case, $\frac{{51 – 49}}{t} = K\left[ {\frac{{51 + 49}}{2} – 30} \right]$ …..$(ii)$
By solving equation $(i)$ and $(ii)$ we get
$t = 6 min$ .
Standard 11
Physics

Similar Questions

Start a Free Trial Now

Confusing about what to choose? Our team will schedule a demo shortly.