In a shop there are five types of ice-creams available. A child buys six ice-creams.
Statement $-1 :$ The number of different ways the child can buy the six ice-creams is $^{10}C_5.$
Statement $-2 :$ The number of different ways the child can buy the six ice-creams is equal to the number of different ways of arranging $6 \,A's$ and $4 \,B's$ in a row.
In a shop there are five types of ice-creams available. A child buys six ice-creams.
Statement $-1 :$ The number of different ways the child can buy the six ice-creams is $^{10}C_5.$
Statement $-2 :$ The number of different ways the child can buy the six ice-creams is equal to the number of different ways of arranging $6 \,A's$ and $4 \,B's$ in a row.
- [AIEEE 2008]
- A
Statement$-1$ is true, Statement$-2$ is false
- B
Statement $-1$ is true, Statement $-2$ is true; Statement $-2$ is a correct explanation for Statement $-1$
- C
Statement $-1$ is true, Statement $-2$ is true; Statement $-2$ is not acorrect explanation for Statement $-1$
- D
Statement$-1$ is false, Statement$-2$ is true
Similar Questions
How many numbers between $5000$ and $10,000$ can be formed using the digits $1, 2, 3, 4, 5, 6, 7, 8, 9$ each digit appearing not more than once in each number
How many numbers between $5000$ and $10,000$ can be formed using the digits $1, 2, 3, 4, 5, 6, 7, 8, 9$ each digit appearing not more than once in each number
If $^n{P_3}{ + ^n}{C_{n - 2}} = 14n$, then $n = $
If $^n{P_3}{ + ^n}{C_{n - 2}} = 14n$, then $n = $
If ${ }^{n} P_{r}={ }^{n} P_{r+1}$ and ${ }^{n} C_{r}={ }^{n} C_{r-1}$, then the value of $r$ is equal to:
If ${ }^{n} P_{r}={ }^{n} P_{r+1}$ and ${ }^{n} C_{r}={ }^{n} C_{r-1}$, then the value of $r$ is equal to:
- [JEE MAIN 2021]
If $\alpha { = ^m}{C_2}$, then $^\alpha {C_2}$is equal to
If $\alpha { = ^m}{C_2}$, then $^\alpha {C_2}$is equal to
The number of ways to give away $25$ apples to $4$ boys, each boy receiving at least $4$ apples, are
The number of ways to give away $25$ apples to $4$ boys, each boy receiving at least $4$ apples, are