6.Permutation and Combination
hard

Total number of $6-$digit numbers in which only and all the five digits $1,3,5,7$ and $9$ appear, is 

A

$\frac{5}{2}(6 !)$

B

$5^6$

C

$\frac{1}{2}(6 !)$

D

$6!$

(JEE MAIN-2020)

Solution

Total number of 6 -digit numbers in which only and all the five digits $1,3,5,7$ and $9$ is

$^{5} \mathrm{C}_{1} \times \frac{6 !}{2 !}$

Standard 11
Mathematics

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