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6.Permutation and Combination
hard
Total number of $6-$digit numbers in which only and all the five digits $1,3,5,7$ and $9$ appear, is
A
$\frac{5}{2}(6 !)$
B
$5^6$
C
$\frac{1}{2}(6 !)$
D
$6!$
(JEE MAIN-2020)
Solution
Total number of 6 -digit numbers in which only and all the five digits $1,3,5,7$ and $9$ is
$^{5} \mathrm{C}_{1} \times \frac{6 !}{2 !}$
Standard 11
Mathematics