Gujarati
11.Thermodynamics
easy

In an adiabatic process $90J$ of work is done on the gas. The change in internal energy of the gas is ....... $J$

A

$-90 $

B

$+90 $

C

$0 $

D

Depends on initial temperature

Solution

(b) For adiabatic process $\Delta Q = 0$

From $\Delta Q = \Delta U + \Delta W$==> $0 = \Delta U – 90$ ==> $\Delta U = + 90J$

Standard 11
Physics

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