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11.Thermodynamics
easy
In an adiabatic process $90J$ of work is done on the gas. The change in internal energy of the gas is ....... $J$
A
$-90 $
B
$+90 $
C
$0 $
D
Depends on initial temperature
Solution
(b) For adiabatic process $\Delta Q = 0$
From $\Delta Q = \Delta U + \Delta W$==> $0 = \Delta U – 90$ ==> $\Delta U = + 90J$
Standard 11
Physics