In an examination, there are 10 true-false ty | vedclass

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Question

$A =\{1,2,3,4\}: P ( A )=\frac{3}{4} ightarrow 	ext { Correct }$

$B =\{5,6,7,8,9,10\} ; P ( B )=\frac{1}{4} 	ext { Correct }$

$8$ Correct&nb

Vedclass · Accepted Answer

$479$

Vedclass · Answer

$A =\{1,2,3,4\}: P ( A )=\frac{3}{4} ightarrow 	ext { Correct }$

$B =\{5,6,7,8,9,10\} ; P ( B )=\frac{1}{4} 	ext { Correct }$

$8$ Correct 

$(4,4):{ }^{4} C _{4}\left(\frac{3}{4}ight)^{4} \cdot{ }^{6} C _{4} \cdot\left(\frac{1}{4}ight)^{4} \cdot\left(\frac{3}{4}ight)^{2}$

$(3,5):{ }^{4} C _{3}\left(\frac{3}{4}ight)^{3} \cdot\left(\frac{1}{4}ight)^{1} \cdot{ }^{6} C _{5}\left(\frac{1}{4}ight)^{5} \cdot\left(\frac{3}{4}ight)$

$(2,6):{ }^{4} C _{2}\left(\frac{3}{4}ight)^{2}\left(\frac{1}{4}ight)^{2} \cdot{ }^{6} C _{6}\left(\frac{1}{4}ight)^{6}$

$\operatorname{Total}=\frac{1}{4^{10}}\left[3^{4} 	imes 15 	imes 3^{2}+4 	imes 3^{3} 	imes 6 	imes 3+6 	imes 3^{2}ight]$

$=\frac{27}{4^{10}}[2.7 	imes 15+72+2]$

$\Rightarrow K =479$

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