Gujarati
6.Permutation and Combination
easy

In an examination there are three multiple choice questions and each question has $4 $ choices. Number of ways in which a student can fail to get all answers correct, is

A

$11$

B

$12$

C

$27$

D

$63$

Solution

(d) Each question can be answered in $4$ ways and all questions can be answered correctly in only one way, so required number of ways $ = {4^3} – 1 = 63$.

Standard 11
Mathematics

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