Gujarati
6.Permutation and Combination
medium

In how many ways a team of $10$ players out of $22$ players can be made if $6$ particular players are always to be included and $4$ particular players are always excluded

A

$^{22}{C_{10}}$

B

$^{18}{C_3}$

C

$^{12}{C_4}$

D

$^{18}{C_4}$

Solution

(c) $6$ particular players are always to be included and $4$ are always excluded so total no. of selection, now, $4$ players out of $12$,

hence number of ways = $^{12}{C_4}$.

Standard 11
Mathematics

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