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6.Permutation and Combination
medium
In how many ways a team of $10$ players out of $22$ players can be made if $6$ particular players are always to be included and $4$ particular players are always excluded
A
$^{22}{C_{10}}$
B
$^{18}{C_3}$
C
$^{12}{C_4}$
D
$^{18}{C_4}$
Solution
(c) $6$ particular players are always to be included and $4$ are always excluded so total no. of selection, now, $4$ players out of $12$,
hence number of ways = $^{12}{C_4}$.
Standard 11
Mathematics