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14.Waves and Sound
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In an experiment with sonometer a tuning fork of frequency $256 Hz$ resonates with a length of $25 cm$ and another tuning fork resonates with a length of $16 cm$. Tension of the string remaining constant the frequency of the second tuning fork is .... $Hz$
A
$163.84$
B
$400$
C
$320$
D
$204.8$
Solution
(b) In case of sonometer frequency is given by
$n = \frac{p}{{2l}}\sqrt {\frac{T}{m}} $
==> $\frac{{{n_2}}}{{{n_1}}} = \frac{{{l_1}}}{{{l_2}}} \Rightarrow {n_2} = \frac{{25}}{{16}} \times 256 = 400\,\,\,Hz$
Standard 11
Physics