In an experiment with Vernier callipers of least count 0.1,mm , when two jaws are joined together ze

English

Gujarati

Hindi

1.Units, Dimensions and Measurement

medium

In an experiment with Vernier callipers of least count $0.1\,mm$, when two jaws are joined together the zero of Vernier scale lies right to the zero of the main scale and $6^{\text {th }}$ division of Vernier scale coincides with the main scale division. While measuring the diameter of a spherical bob, the zero of vernier scale lies in between $3.2\,cm$ and $3.3\,cm$ marks, and $4^{\text {th }}$ division of vernier scale coincides with the main scale division. The diameter of bob is measured as $.......\,cm$

A

$3.18$

B

$3.25$

C

$3.26$

D

$3.22$

(JEE MAIN-2023)

Solution

$LC =0.1\,mm$

$\text { Zero Error }=6 \times LC =0.6\,mm$

$\text { Reading }= MSR + VSR \times LC -\text { Zero Error }$

$=[32\,mm +(0.1) 4\,mm ]-0.6\,mm$
$=31.8\,mm$

$=3.18\,cm$

Standard 11

Physics

Share

Similar Questions

The density of a solid ball is to be determined in an experiment. The diameter of the ball is measured with a screw gauge, whose pitch is $0.5 \ mm$ and there are $50$ divisions on the circular scale. The reading on the main scale is $2.5 \ mm$ and that on the circular scale is $20$ divisions. If the measured mass of the ball has a relative error of $2 \%$, the relative percentage error in the density is

hard

(IIT-2011)

Area of the cross-section of a wire is measured using a screw gauge. The pitch of the main scale is $0.5 mm$. The circular scale has 100 divisions and for one full rotation of the circular scale, the main scale shifts by two divisions. The measured readings are listed below.

Measurement condition Main scale reading Circular scale reading

Two arms of gauge touching each other without wire $0$ division $4$ division

Attempt-$1$: With wire $4$ division $20$ division

Attempt-$2$: With wire $4$ division $16$ division

What are the diameter and cross-sectional area of the wire measured using the screw gauge?

normal

(IIT-2022)

A screw gauge gives the following reading when used to measure the diameter of a wire.

Main scale reading : $0\ mm$

Circular scale reading : $52\ divisions$

Given that $1\ mm$ on main scale corresponds to $100$ divisions of the circular scale. The diameter of wire from the above data is:

medium

(AIEEE-2011)

A student performs an experiment of measuring the thickness of a slab with a vernier calliper whose $50$ divisions of the vernier scale are equal to $49$ divisions of the main scale. He noted that zero of the vernier scale is between $7.00\; cm$ and $7.05 \;cm$ mark of the main scale and $23^{rd}$ division of the vernier scale exactly coincides with the main scale. The measured value of the thickness of the given slab using the calliper will be

medium

(NEET-2017)

When the gap is closed without placing any object in the screw gauge whose least count is $0.005\ mm$, the $5^{th}$ division on its circular scale with the reference line on main scale, and when a small sphere is placed reading on main scale advances by $4$ divisions, whereas circular scale reading advances by five times to the corresponding reading when no object was placed. There are $200$ divisions on the circular scale. The radius of the sphere is ………. $mm$

hard