- Home
- Standard 11
- Mathematics
6.Permutation and Combination
easy
In how many ways can a girl and a boy be selected from a group of $15$ boys and $8 $ girls
A
$15 \times 8$
B
$15 + 8$
C
$^{23}{P_2}$
D
$^{23}{C_2}$
Solution
(a) Required number of ways${ = ^{15}}{C_1}{ \times ^8}{C_1} = \,15 \times \,8$.
Standard 11
Mathematics