In Millikan’s oil drop experiment, an oil drop of mass $16 \times {10^{ - 6}}kg$ is balanced by an electric field of ${10^6}V/m.$ The charge in coulomb on the drop, assuming $g = 10\,m/{s^2}$ is
In Millikan’s oil drop experiment, an oil drop of mass $16 \times {10^{ - 6}}kg$ is balanced by an electric field of ${10^6}V/m.$ The charge in coulomb on the drop, assuming $g = 10\,m/{s^2}$ is
- A
$6.2 \times {10^{ - 11}}$
- B
$16 \times {10^{ - 9}}$
- C
$16 \times {10^{ - 11}}$
- D
$16 \times {10^{ - 13}}$
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