Gujarati
Hindi
7.Gravitation
normal

In order to shift a body of mass $m$ from a circular orbit of radius $3R$ to a higher radius $5R$ around the earth, the work done is

A

$\frac {3GMm}{5R}$

B

$\frac {1}{15} \frac {GMm}{R}$

C

$\frac {GMm}{2R}$

D

$\frac {GMm}{5R}$

Solution

$W = \Delta ME =  – \frac{{GMm}}{{2(5R)}} – \left( { – \frac{{GMm}}{{2(3R)}}} \right) = \frac{1}{{15}}\frac{{GMm}}{R}$

Standard 11
Physics

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