- Home
- Standard 11
- Physics
7.Gravitation
normal
In order to shift a body of mass $m$ from a circular orbit of radius $3R$ to a higher radius $5R$ around the earth, the work done is
A
$\frac {3GMm}{5R}$
B
$\frac {1}{15} \frac {GMm}{R}$
C
$\frac {GMm}{2R}$
D
$\frac {GMm}{5R}$
Solution
$W = \Delta ME = – \frac{{GMm}}{{2(5R)}} – \left( { – \frac{{GMm}}{{2(3R)}}} \right) = \frac{1}{{15}}\frac{{GMm}}{R}$
Standard 11
Physics