In photo electric effect
$A.$ The photocurrent is proportional to the intensity of the incident radiation.
$B.$ Maximum Kinetic energy with which photoelectrons are emitted depends on the intensity of incident light.
$C.$ Max. $K.E$ with which photoelectrons are emitted depends on the frequency of incident light.
$D.$ The emission of photoelectrons require a minimum threshold intensity of incident radiation.
$E.$ Max. K.E of the photoelectrons is independent of the frequency of the incident light.
Choose the correct answer from the options given below:
In photo electric effect
$A.$ The photocurrent is proportional to the intensity of the incident radiation.
$B.$ Maximum Kinetic energy with which photoelectrons are emitted depends on the intensity of incident light.
$C.$ Max. $K.E$ with which photoelectrons are emitted depends on the frequency of incident light.
$D.$ The emission of photoelectrons require a minimum threshold intensity of incident radiation.
$E.$ Max. K.E of the photoelectrons is independent of the frequency of the incident light.
Choose the correct answer from the options given below:
- [JEE MAIN 2023]
- A
$A$ and $C$ only
- B
$A$ and $E$ only
- C
$B$ and $C$ only
- D
$A$ and $B$ only
Similar Questions
$(i)$ In the explanation of photoelectric effect, we assume one photon of frequency v collides with an electron and transfers its energy. This leads to the equation for the maximum energy Emax of the emitted electron as $E_{max} = hf - \phi _0$ (where $\phi _0$ where do is the work function of the metal. If an electron absorbs $2$ photons (each of frequency $v$) what will be the maximum energy for the emitted electron ?
$(ii)$ Why is this fact (two photon absorption) not taken into consideration in our discussion of the stopping potential ?
$(i)$ In the explanation of photoelectric effect, we assume one photon of frequency v collides with an electron and transfers its energy. This leads to the equation for the maximum energy Emax of the emitted electron as $E_{max} = hf - \phi _0$ (where $\phi _0$ where do is the work function of the metal. If an electron absorbs $2$ photons (each of frequency $v$) what will be the maximum energy for the emitted electron ?
$(ii)$ Why is this fact (two photon absorption) not taken into consideration in our discussion of the stopping potential ?
The energy equivalent to $1\,mg$ of matter in $MeV$ is
The energy equivalent to $1\,mg$ of matter in $MeV$ is
The energy of a photon of light with wavelength $5000\, \mathring A$ is approximately $2.5 eV$. This way the energy of an $X-$ ray photon with wavelength $1\, \mathring A $ would be
Match the column
$(A)$ Hallwachs $\&$ Lenard
$(P)$ Transformers
$(B)$ Franck-Hertz
$(Q)$ Microwave
$(C)$ Klystron valve
$(R)$ Quantization of energy levels
$(D)$ Nicola Tesla
$(S)$ Photoelectric effect
Match the column
| $(A)$ Hallwachs $\&$ Lenard | $(P)$ Transformers |
| $(B)$ Franck-Hertz | $(Q)$ Microwave |
| $(C)$ Klystron valve | $(R)$ Quantization of energy levels |
| $(D)$ Nicola Tesla | $(S)$ Photoelectric effect |