In adjoining figure if acceleration of M with respect to ground is a , then

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4-1.Newton's Laws of Motion

hard

In the adjoining figure if acceleration of $M$ with respect to ground is $a$, then

A

acceleration of $m$ with respect to $M$ is $2a$

B

acceleration of $m$ with respect to ground is $2a \ sin (\alpha/2)$

C

acceleration of $m$ with respect to ground is $a$

D

acceleration of $m$ with respect to ground is $a\, tan \alpha$

Solution

$a_{0}=\sqrt{a^{2}+a^{2}+2 a^{2} \cos (\pi-\alpha)}$

$a_{0}=2 a \sin \left(\frac{\alpha}{2}\right)$

Standard 11

Physics

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