For the given diagram when block $B$ is pulled with velocity $V$ then velocity of block $A$ will be :-
$V$
$\frac{V}{\sqrt 3}$
$V \sqrt 3$
$\frac{\sqrt 3}{2}V$
Find the acceleration of $B$.
Two particles $A$ and $B$ are connected by rigid rod $A B$. The rod slides along perpendicular rails as shown here. The velocity of $A$ to the left is $10\; m / s$. What is the velocity of $B$(in $m/s$) when angle $\alpha=60^{\circ}$?
In the adjoining figure if acceleration of $M$ with respect to ground is $a$, then
In the arrangement shown in fig. the ends $P$ and $Q$ of an unstretchable string move downwards with uniform speed $U$. Pulleys $A$ and $B$ are fixed. Mass $M$ moves upwards with a speed.