Consider situation shown. switch S is opened for a long time and then closed. charge flown through b

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1. Electric Charges and Fields

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Consider the situation shown. The switch $S$ is opened for a long time and then closed. The charge flown through the battery when $S$ is closed

A

$CE$

B

$\frac{{CE}}{2}$

C

$\frac{{CE}}{3}$

D

$\frac{{CE}}{4}$

Solution

Initial charge supply by battery

$\mathrm{Q}_{1}=\frac{\mathrm{CV}}{2}$

Final charge supply by battery

$\mathrm{Q}_{2}=\mathrm{CV}$

$\Delta \mathrm{Q}=\mathrm{Q}_{2}-\mathrm{Q}_{1}=\frac{\mathrm{CV}}{2}$

Standard 12

Physics

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