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4.Chemical Bonding and Molecular Structure
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In the conversion of $N_2$ into $N_2^+$ the electron will be lost from which of the following molecular orbital ?
A
${\sigma ^ * }2{p_z}$
B
$\sigma 2{p_z}$
C
$\pi 2{p_x}$
D
${\pi ^ * }2{p_x}$
Solution
The elctronic configuration of
$\mathrm{N}_{2}=\mathrm{KK} \sigma 2 \mathrm{s}^{2} \sigma^{*} 2 \mathrm{s}^{2} \pi 2 \mathrm{p}_{\mathrm{x}}^{2}=\pi 2 \mathrm{p}_{\mathrm{y}}^{2} \sigma 2 \mathrm{p}_{\mathrm{z}}^{2}$
$\mathrm{N}_{2}^{+}=\mathrm{KK} \sigma 2 \mathrm{s}^{2} \sigma^{*} 2 \mathrm{s}^{2} \pi 2 \mathrm{p}_{\mathrm{x}}^{2}=\pi 2 \mathrm{p}_{\mathrm{y}}^{2} \sigma 2 \mathrm{p}_{\mathrm{z}}^{1}$
Standard 11
Chemistry
