In the conversion of N_2 into N_2^+ the elect | vedclass

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Question

The elctronic configuration of

$\mathrm{N}_{2}=\mathrm{KK} \sigma 2 \mathrm{s}^{2} \sigma^{*} 2 \mathrm{s}^{2} \pi 2 \mathrm{p}_{\mathrm{x}}^{2}=\p

Vedclass · Accepted Answer

$\sigma 2{p_z}$

Vedclass · Answer

The elctronic configuration of

$\mathrm{N}_{2}=\mathrm{KK} \sigma 2 \mathrm{s}^{2} \sigma^{*} 2 \mathrm{s}^{2} \pi 2 \mathrm{p}_{\mathrm{x}}^{2}=\pi 2 \mathrm{p}_{\mathrm{y}}^{2} \sigma 2 \mathrm{p}_{\mathrm{z}}^{2}$

$\mathrm{N}_{2}^{+}=\mathrm{KK} \sigma 2 \mathrm{s}^{2} \sigma^{*} 2 \mathrm{s}^{2} \pi 2 \mathrm{p}_{\mathrm{x}}^{2}=\pi 2 \mathrm{p}_{\mathrm{y}}^{2} \sigma 2 \mathrm{p}_{\mathrm{z}}^{1}$

In the conversion of $N_2$ into $N_2^+$ the electron will be lost from which of the following molecular orbital ?

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