In the expansion of $(1+x)\left(1-x^2\right)\left(1+\frac{3}{x}+\frac{3}{x^2}+\frac{1}{x^3}\right)^5, x \neq 0$, the sum of the coefficient of $x^3$ and $x^{-13}$ is equal to

  • [JEE MAIN 2024]
  • A

    $118$

  • B

    $116$

  • C

    $115$

  • D

    $117$

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